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D( x )
x+1 = 0
x+1 = 0
x+1 = 0
x+1 = 0 // - 1
x = -1
x in (-oo:-1) U (-1:+oo)
((2*x+5)*(5*x-2))/(x+1) = 0
( 2*x+5 )
2*x+5 = 0 // - 5
2*x = -5 // : 2
x = -5/2
( 5*x-2 )
5*x-2 = 0 // + 2
5*x = 2 // : 5
x = 2/5
x in { -5/2, 2/5 }
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