(((2x+60)+(3x+10)=180)*2))+(7)

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Solution for (((2x+60)+(3x+10)=180)*2))+(7) equation: 



(((2x+60)+(3x+10)=180)*2))+(7)

We move all terms to the left:

(((2x+60)+(3x+10)-(180)*2))+(7))=0

We add all the numbers together, and all the variables

(((2x+60)+(3x+10)-180*2))=0



We calculate terms in parentheses: +(((2x+60)+(3x+10)-180*2)), so:

((2x+60)+(3x+10)-180*2)



We calculate terms in parentheses: +((2x+60)+(3x+10)-180*2), so:

(2x+60)+(3x+10)-180*2

We add all the numbers together, and all the variables

(2x+60)+(3x+10)-360

We get rid of parentheses

2x+3x+60+10-360

We add all the numbers together, and all the variables

5x-290

Back to the equation:

+(5x-290)



We get rid of parentheses

5x-290

Back to the equation:

+(5x-290)



We get rid of parentheses

5x-290=0

We move all terms containing x to the left, all other terms to the right

5x=290

x=290/5

x=58

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