(((3/2x)(3))-(12))=18

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Solution for (((3/2x)(3))-(12))=18 equation: 



(((3/2x)(3))-(12))=18

We move all terms to the left:

(((3/2x)(3))-(12))-(18)=0



Domain of the equation: 2x)3)-12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(((+3/2x)3)-12)-18=0

We multiply all the terms by the denominator


(((+3-18*2x)3)-12)=0



We calculate terms in parentheses: +(((+3-18*2x)3)-12), so:

((+3-18*2x)3)-12

We add all the numbers together, and all the variables

((-18*2x+3)3)-12



We calculate terms in parentheses: +((-18*2x+3)3), so:

(-18*2x+3)3

We multiply parentheses

-108x+9

Back to the equation:

+(-108x+9)



We get rid of parentheses

-108x+9-12

We add all the numbers together, and all the variables

-108x-3

Back to the equation:

+(-108x-3)



We get rid of parentheses

-108x-3=0

We move all terms containing x to the left, all other terms to the right

-108x=3

x=3/-108

x=-1/36

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