(((3t)/(3t-3))-((1)/(9t+3)))=1

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Solution for (((3t)/(3t-3))-((1)/(9t+3)))=1 equation:


D( t )

3*t-3 = 0

9*t+3 = 0

3*t-3 = 0

3*t-3 = 0

3*t-3 = 0 // + 3

3*t = 3 // : 3

t = 3/3

t = 1

9*t+3 = 0

9*t+3 = 0

9*t+3 = 0 // - 3

9*t = -3 // : 9

t = -3/9

t = -1/3

t in (-oo:-1/3) U (-1/3:1) U (1:+oo)

(3*t)/(3*t-3)-(1/(9*t+3)) = 1 // - 1

(3*t)/(3*t-3)-(1/(9*t+3))-1 = 0

(3*t)/(3*t-3)-(9*t+3)^-1-1 = 0

(3*t)/(3*t-3)-1/(9*t+3)-1 = 0

(3*t*(9*t+3))/((3*t-3)*(9*t+3))+(-1*(3*t-3))/((3*t-3)*(9*t+3))+(-1*(3*t-3)*(9*t+3))/((3*t-3)*(9*t+3)) = 0

3*t*(9*t+3)-1*(3*t-3)-1*(3*t-3)*(9*t+3) = 0

27*t^2-27*t^2+6*t+18*t+3+9 = 0

24*t+12 = 0

(24*t+12)/((3*t-3)*(9*t+3)) = 0

(24*t+12)/((3*t-3)*(9*t+3)) = 0 // * (3*t-3)*(9*t+3)

24*t+12 = 0

24*t+12 = 0 // - 12

24*t = -12 // : 24

t = -12/24

t = -1/2

t = -1/2

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