(((t+5)/(8)))-(((t-2)/(2)))=1/3

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Solution for (((t+5)/(8)))-(((t-2)/(2)))=1/3 equation: 


t in (-oo:+oo)

(t+5)/8-((t-2)/2) = 1/3 // - 1/3

(t+5)/8-((t-2)/2)-(1/3) = 0

(t+5)/8-((t-2)/2)-1/3 = 0

(t+5)/8+(-1*(t-2))/2-1/3 = 0

(2*3*(t+5))/(2*3*8)+(-1*3*8*(t-2))/(2*3*8)+(-1*2*8)/(2*3*8) = 0

2*3*(t+5)-1*3*8*(t-2)-1*2*8 = 0

78-18*t-16 = 0

62-18*t = 0

(62-18*t)/(2*3*8) = 0

(62-18*t)/(2*3*8) = 0 // * 2*3*8

62-18*t = 0

62-18*t = 0 // - 62

-18*t = -62 // : -18

t = -62/(-18)

t = 31/9

t = 31/9

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