((-(2/9))(m))+12=-8

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Solution for ((-(2/9))(m))+12=-8 equation:



((-(2/9))(m))+12=-8
We move all terms to the left:
((-(2/9))(m))+12-(-8)=0
Domain of the equation: 9))m)!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
((-(+2/9))m)+12-(-8)=0
We add all the numbers together, and all the variables
((-(+2/9))m)+20=0
We multiply all the terms by the denominator
((-(+2+20*9))m)=0
We calculate terms in parentheses: +((-(+2+20*9))m), so:
(-(+2+20*9))m
We add all the numbers together, and all the variables
(-182)m
We multiply parentheses
-182m
Back to the equation:
+(-182m)
We get rid of parentheses
-182m=0
m=0/-182
m=0
Równanie nie ma rozwiązania

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