((-(2/9))(m))+12=-8

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Solution for ((-(2/9))(m))+12=-8 equation: 



((-(2/9))(m))+12=-8

We move all terms to the left:

((-(2/9))(m))+12-(-8)=0



Domain of the equation: 9))m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

((-(+2/9))m)+12-(-8)=0

We add all the numbers together, and all the variables

((-(+2/9))m)+20=0

We multiply all the terms by the denominator


((-(+2+20*9))m)=0



We calculate terms in parentheses: +((-(+2+20*9))m), so:

(-(+2+20*9))m

We add all the numbers together, and all the variables

(-182)m

We multiply parentheses

-182m

Back to the equation:

+(-182m)



We get rid of parentheses

-182m=0

m=0/-182

m=0

Równanie nie ma rozwiązania

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