((-1)-12)(5x-4)=20

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Solution for ((-1)-12)(5x-4)=20 equation:



((-1)-12)(5x-4)=20
We move all terms to the left:
((-1)-12)(5x-4)-(20)=0
We calculate terms in parentheses: +((-1)-12)(5x-4), so:
(-1)-12)(5x-4
determiningTheFunctionDomain -12)(5x-4+(-1)
We add all the numbers together, and all the variables
-12)(5x-5
Back to the equation:
+(-12)(5x-5)
We multiply parentheses ..
(-60x+60)-20=0
We get rid of parentheses
-60x+60-20=0
We add all the numbers together, and all the variables
-60x+40=0
We move all terms containing x to the left, all other terms to the right
-60x=-40
x=-40/-60
x=2/3

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