((-3j)-(-4))/6=12

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Solution for ((-3j)-(-4))/6=12 equation:



((-3j)-(-4))/6=12
We move all terms to the left:
((-3j)-(-4))/6-(12)=0
We multiply all the terms by the denominator
((-3j)-(-4))-12*6=0
We calculate terms in parentheses: +((-3j)-(-4)), so:
(-3j)-(-4)
We add all the numbers together, and all the variables
(-3j)+4
We get rid of parentheses
-3j+4
Back to the equation:
+(-3j+4)
We add all the numbers together, and all the variables
(-3j+4)-72=0
We get rid of parentheses
-3j+4-72=0
We add all the numbers together, and all the variables
-3j-68=0
We move all terms containing j to the left, all other terms to the right
-3j=68
j=68/-3
j=-22+2/3

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