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((-6y+15)/5)-4y=29
We move all terms to the left:
((-6y+15)/5)-4y-(29)=0
We add all the numbers together, and all the variables
-4y+((-6y+15)/5)-29=0
We multiply all the terms by the denominator
-4y*5)+((-6y+15)-29*5)=0
We add all the numbers together, and all the variables
-4y*5)+((-6y+15)=0
Wy multiply elements
-20y^2=0
a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{-40}=0$
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