If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((1)/((4)))n-3=25
We move all terms to the left:
((1)/((4)))n-3-(25)=0
Domain of the equation: (4))n!=0determiningTheFunctionDomain (1/4)n-3-25=0
n∈R
We add all the numbers together, and all the variables
(+1/4)n-3-25=0
We add all the numbers together, and all the variables
(+1/4)n-28=0
We multiply parentheses
n^2-28=0
a = 1; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·1·(-28)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{7}}{2*1}=\frac{0-4\sqrt{7}}{2} =-\frac{4\sqrt{7}}{2} =-2\sqrt{7} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{7}}{2*1}=\frac{0+4\sqrt{7}}{2} =\frac{4\sqrt{7}}{2} =2\sqrt{7} $
| 2x+56=x+22 | | 5b-6=8-b | | p^2=94 | | 3^(x-4)+7=2 | | 8(x+5)=128 | | 5(x+16)=65 | | 3^(x-4)+7=12 | | x2-10x=2 | | -5k+7=38 | | y=6(45)+20 | | y=3/2(45)+20 | | X+43=8x+36 | | 5/d=(-10)/7 | | 50+180-11x=12x | | 4(3a+9)=120 | | (-2c-6)/2=4 | | -8=4.x | | 0.4+-2.7x=2.8+-1.2x | | y=7= | | 3x/4x+12=21 | | y=6+0.25 | | 4x(x+1)=-2(x-26) | | 8-3x=14-4x. | | 1/2b-10=20 | | 3(p+1)=5(p+1) | | x^2-8=-6 | | (x+16)(x-22)=0 | | x−35=125 | | (x+8)/3=2 | | 6x+10=26-2x | | 7x-11=21 | | r·1=0.1 |