((1)/(3x))+((1)/(2x))=(1/6)-(1/x)

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Solution for ((1)/(3x))+((1)/(2x))=(1/6)-(1/x) equation: 


D( x )

3*x = 0

x = 0

2*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x = 0

x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

1/(3*x)+1/(2*x) = 1/6-(1/x) // - 1/6-(1/x)

1/(3*x)+1/(2*x)+1/x-(1/6) = 0

1/(3*x)+1/(2*x)+1/x-1/6 = 0

11/6*x^-1 = 1/6 // : 11/6

x^-1 = 1/11

-1 < 0

1/(x^1) = 1/11 // * x^1

1 = 1/11*x^1 // : 1/11

11 = x^1

x = 11

x = 11

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