((1/2)x+4)+((3/4)x-6)=2x-47

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Solution for ((1/2)x+4)+((3/4)x-6)=2x-47 equation: 



((1/2)x+4)+((3/4)x-6)=2x-47

We move all terms to the left:

((1/2)x+4)+((3/4)x-6)-(2x-47)=0



Domain of the equation: 2)x+4)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x-6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((+1/2)x+4)+((+3/4)x-6)-(2x-47)=0

We get rid of parentheses

((+1/2)x+4)+((+3/4)x-6)-2x+47=0

We calculate fractions


-2x+(4x-6)/2x+4)*4)x-6))+(6x+4)/2x+4)*4)x-6))+47=0

We calculate fractions


-2x+(8x^2-12x+4)*4)x-6))+47)/(4x^2+4)*4)x-6))+47)+4*4)x-6))+(6x+4)*2x)/(4x^2+4)*4)x-6))+47)=0

We can not solve this equation

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