((1/2+x)+4)+((3/4+x)-6)=2x-47

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Solution for ((1/2+x)+4)+((3/4+x)-6)=2x-47 equation: 



((1/2+x)+4)+((3/4+x)-6)=2x-47

We move all terms to the left:

((1/2+x)+4)+((3/4+x)-6)-(2x-47)=0



Domain of the equation: 2+x)+4)!=0

We move all terms containing x to the left, all other terms to the right

x)+4)!=-2

x!=-2/1

x!=-2

x∈R





Domain of the equation: 4+x)-6)!=0

We move all terms containing x to the left, all other terms to the right

x)-6)!=-4

x!=-4/1

x!=-4

x∈R



We add all the numbers together, and all the variables

((+x+1/2)+4)+((+x+3/4)-6)-(2x-47)=0

We get rid of parentheses

((+x+1/2)+4)+((+x+3/4)-6)-2x+47=0

We calculate fractions


-2x+(x-2)/()+(x+10)/()+47=0

We multiply all the terms by the denominator


-2x*()+(x-2)+(x+10)+47*()=0

We add all the numbers together, and all the variables

-2x*()+(x-2)+(x+10)=0

We get rid of parentheses

-2x*()+x+x-2+10=0

We add all the numbers together, and all the variables

2x-2x*()+8=0

We move all terms containing x to the left, all other terms to the right

2x-2x*()=-8

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