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((1/3)*((2/5)*x-(1/5)))/(1/15) = 0
((1/3)*((2/5)*x-1/5))/(1/15) = 0
(1/3*(2/5*x-1/5))/1/15 = 0
( 1/3 )
1/3 = 0
x belongs to the empty set
( 2/5*x-1/5 )
2/5*x-1/5 = 0 // + 1/5
2/5*x = 1/5 // : 2/5
x = 1/5/2/5
x = 1/2
x = 1/2
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