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((1/3))6x+5=9x-2
We move all terms to the left:
((1/3))6x+5-(9x-2)=0
Domain of the equation: 3))6x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((+1/3))6x-(9x-2)+5=0
We get rid of parentheses
((+1/3))6x-9x+2+5=0
We multiply all the terms by the denominator
((+1-9x*3))6x+2*3))6x+5*3))6x=0
We add all the numbers together, and all the variables
((-9x*3+1))6x+2*3))6x+5*3))6x=0
Wy multiply elements
18x^2+((-9x*3+1))6x=0
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