((1/3)+(1/x))/(3+x)

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Solution for ((1/3)+(1/x))/(3+x) equation: 


D( x )

x = 0

x+3 = 0

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

(1/x+1/3)/(x+3) = 0

(x^-1+1/3)/(x+3) = 0

1*x^-1 = -1/3 // : 1

x^-1 = -1/3

-1 < 0

1/(x^1) = -1/3 // * x^1

1 = -1/3*x^1 // : -1/3

-3 = x^1

x = -3

x in { -3} 

x belongs to the empty set

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