((1/6)*d)+(2/3)=((1/4)*(d-2))

Solution for ((1/6)*d)+(2/3)=((1/4)*(d-2)) equation:

((1/6)*d)+(2/3)=((1/4)(d-2))

We move all terms to the left:

((1/6)*d)+(2/3)-(((1/4)(d-2)))=0


Domain of the equation: 6)*d)!=0

d!=0/1

d!=0

d∈R



Domain of the equation: 4)(d-2)))!=0

d∈R


We add all the numbers together, and all the variables

((+1/6)*d)-(((+1/4)(d-2)))+(+2/3)=0

We get rid of parentheses

((+1/6)*d)-(((+1/4)(d-2)))+2/3=0

We multiply parentheses ..

-(((+d^2+1/4*-2)))+((+1/6)*d)+2/3=0

We calculate fractions


(-(((+d^2+1*6)*d)*3)/(-2)))*6)*d)*3+4*)+()/(-2)))*6)*d)*3+4*)+(-2)))*6)*d)+2*4*)/(-2)))*6)*d)*3+4*)=0


We calculate terms in parentheses: +(-(((+d^2+1*6)*d)*3)/(-2)))*6)*d)*3+4*)+()/(-2)))*6)*d)*3+4*)+(-2)))*6)*d)+2*4*)/(-2)))*6)*d)*3+4*), so:

-(((+d^2+1*6)*d)*3)/(-2)))*6)*d)*3+4*)+()/(-2)))*6)*d)*3+4*)+(-2)))*6)*d)+2*4*)/(-2)))*6)*d)*3+4*

We can not solve this equation