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((10+3x)/5)+3=4x
We move all terms to the left:
((10+3x)/5)+3-(4x)=0
We add all the numbers together, and all the variables
((3x+10)/5)-4x+3=0
We add all the numbers together, and all the variables
-4x+((3x+10)/5)+3=0
We multiply all the terms by the denominator
-4x*5)+((3x+10)+3*5)=0
We add all the numbers together, and all the variables
-4x*5)+((3x+10)=0
Wy multiply elements
-20x^2=0
a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-40}=0$
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