((108+2x)/4)+2x)/3=70

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Solution for ((108+2x)/4)+2x)/3=70 equation: 



((108+2x)/4)+2x)/3=70

We move all terms to the left:

((108+2x)/4)+2x)/3-(70)=0

We add all the numbers together, and all the variables

((2x+108)/4)+2x)/3-70=0

We calculate fractions


(((2x+108)*3-70)/()+2x*4))/()=0



We calculate terms in parentheses: +(((2x+108)*3-70)/()+2x*4))/(), so:

((2x+108)*3-70)/()+2x*4))/(

We calculate fractions

We do not support expression: x^3

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