((10t+8)/6)-4=2t+2

Solution for ((10t+8)/6)-4=2t+2 equation:

((10t+8)/6)-4=2t+2

We move all terms to the left:

((10t+8)/6)-4-(2t+2)=0

We get rid of parentheses

((10t+8)/6)-2t-2-4=0

We multiply all the terms by the denominator


((10t+8)-2t*6)-2*6)-4*6)=0


We calculate terms in parentheses: +((10t+8)-2t*6), so:

(10t+8)-2t*6

Wy multiply elements

(10t+8)-12t

We get rid of parentheses

10t-12t+8

We add all the numbers together, and all the variables

-2t+8

Back to the equation:

+(-2t+8)


We add all the numbers together, and all the variables

(-2t+8)=0

We get rid of parentheses

-2t+8=0

We move all terms containing t to the left, all other terms to the right

-2t=-8

t=-8/-2

t=+4