((10x-4)/2)+7=5(x+1)

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Solution for ((10x-4)/2)+7=5(x+1) equation:



((10x-4)/2)+7=5(x+1)
We move all terms to the left:
((10x-4)/2)+7-(5(x+1))=0
We multiply all the terms by the denominator
((10x-4)-((5(x+1)))*2)+7*2)=0
We calculate terms in parentheses: +((10x-4)-((5(x+1)))*2), so:
(10x-4)-((5(x+1)))*2
We get rid of parentheses
10x-((5(x+1)))*2-4
Back to the equation:
+(10x-((5(x+1)))*2-4)
We add all the numbers together, and all the variables
(10x-((5(x+1)))*2-4)=0
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4
We calculate terms in parentheses: +(10x-((5(x+1)))*2-4), so:
10x-((5(x+1)))*2-4

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