((13(x-3))-7(x+3))/(13(x+3))=0

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Solution for ((13(x-3))-7(x+3))/(13(x+3))=0 equation: 



((13(x-3))-7(x+3))/(13(x+3))=0



Domain of the equation: (13(x+3))!=0

x∈R



We multiply all the terms by the denominator


((13(x-3))-7(x+3))=0



We calculate terms in parentheses: +((13(x-3))-7(x+3)), so:

(13(x-3))-7(x+3)

We multiply parentheses

(13(x-3))-7x-21



We calculate terms in parentheses: +(13(x-3)), so:

13(x-3)

We multiply parentheses

13x-39

Back to the equation:

+(13x-39)



We add all the numbers together, and all the variables

-7x+(13x-39)-21

We get rid of parentheses

-7x+13x-39-21

We add all the numbers together, and all the variables

6x-60

Back to the equation:

+(6x-60)



We get rid of parentheses

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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