((16)/(4x-3))=((4)/(x))

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Solution for ((16)/(4x-3))=((4)/(x)) equation: 


D( x )

x = 0

4*x-3 = 0

x = 0

x = 0

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0 // + 3

4*x = 3 // : 4

x = 3/4

x in (-oo:0) U (0:3/4) U (3/4:+oo)

16/(4*x-3) = 4/x // - 4/x

16/(4*x-3)-(4/x) = 0

16/(4*x-3)-4*x^-1 = 0

16/(4*x-3)-4/x = 0

(16*x)/(x*(4*x-3))+(-4*(4*x-3))/(x*(4*x-3)) = 0

16*x-4*(4*x-3) = 0

12 = 0

12/(x*(4*x-3)) = 0

12/(x*(4*x-3)) = 0 // * x*(4*x-3)

12 = 0

x belongs to the empty set

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