((16+x)/16)=1+(x/16)

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Solution for ((16+x)/16)=1+(x/16) equation: 


x in (-oo:+oo)

(x+16)/16 = x/16+1 // - x/16+1

(x+16)/16-(x/16)-1 = 0

(x+16)/16-x/16-1 = 0

(x+16)/16-x/16+(-1*16)/16 = 0

x-x-1*16+16 = 0

16-16 = 0

0 = 0

0/16 = 0

0/16 = 0 // * 16

0 = 0

x belongs to the empty set

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