((2)+(3*5)+(11*12.5)+(13*62,5))/28=x

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Solution for ((2)+(3*5)+(11*12.5)+(13*62,5))/28=x equation: 



((2)+(3*5)+(11*12.5)+(13*62.5))/28=x

We move all terms to the left:

((2)+(3*5)+(11*12.5)+(13*62.5))/28-(x)=0

We add all the numbers together, and all the variables

-x+(2+15+(137.5)+(812.5))/28=0

We add all the numbers together, and all the variables

-1x+(2+15+(137.5)+(812.5))/28=0

We multiply all the terms by the denominator


-1x*28+(2+15+(137.5)+(812.5))=0



We calculate terms in parentheses: +(2+15+(137.5)+(812.5)), so:

2+15+(137.5)+(812.5)

We add all the numbers together, and all the variables

967

Back to the equation:

+(967)



Wy multiply elements

-28x+967=0

We move all terms containing x to the left, all other terms to the right

-28x=-967

x=-967/-28

x=34+15/28

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