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((2)/(2x)+5)=(4/x)
We move all terms to the left:
((2)/(2x)+5)-((4/x))=0
Domain of the equation: 2x+5)!=0
x∈R
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(2/2x+5)-((+4/x))=0
We get rid of parentheses
2/2x-((+4/x))+5=0
We calculate fractions
2x/2x^2+(-((+4*2x)/2x^2+5=0
We calculate fractions
We do not support expression: x^4
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