((2-2x)/9)=10

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Solution for ((2-2x)/9)=10 equation: 



((2-2x)/9)=10

We move all terms to the left:

((2-2x)/9)-(10)=0

We add all the numbers together, and all the variables

((-2x+2)/9)-10=0

We multiply all the terms by the denominator


((-2x+2)-10*9)=0



We calculate terms in parentheses: +((-2x+2)-10*9), so:

(-2x+2)-10*9

We add all the numbers together, and all the variables

(-2x+2)-90

We get rid of parentheses

-2x+2-90

We add all the numbers together, and all the variables

-2x-88

Back to the equation:

+(-2x-88)



We get rid of parentheses

-2x-88=0

We move all terms containing x to the left, all other terms to the right

-2x=88

x=88/-2

x=-44

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