((2-3x)/7)+((x-1)/3)=(3x)/7

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Solution for ((2-3x)/7)+((x-1)/3)=(3x)/7 equation: 


x in (-oo:+oo)

(2-(3*x))/7+(x-1)/3 = (3*x)/7 // - (3*x)/7

(2-(3*x))/7+(x-1)/3-((3*x)/7) = 0

(2-3*x)/7+(x-1)/3+(-3/7)*x = 0

(2-3*x)/7+(x-1)/3+(-3*x)/7 = 0

(3*(2-3*x))/(3*7)+(7*(x-1))/(3*7)+(-3*3*x)/(3*7) = 0

3*(2-3*x)+7*(x-1)-3*3*x = 0

-2*x-9*x-1 = 0

-11*x-1 = 0

(-11*x-1)/(3*7) = 0

(-11*x-1)/(3*7) = 0 // * 3*7

-11*x-1 = 0

-11*x-1 = 0 // + 1

-11*x = 1 // : -11

x = 1/(-11)

x = -1/11

x = -1/11

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