((2-9z)/(17-4z))=4/5

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Solution for ((2-9z)/(17-4z))=4/5 equation: 



((2-9z)/(17-4z))=4/5

We move all terms to the left:

((2-9z)/(17-4z))-(4/5)=0



Domain of the equation: (17-4z))!=0

We move all terms containing z to the left, all other terms to the right

-4z)!=-17

z!=-17/1

z!=-17

z∈R



We add all the numbers together, and all the variables

((-9z+2)/(-4z+17))-(+4/5)=0

We get rid of parentheses

((-9z+2)/(-4z+17))-4/5=0

We calculate fractions


(((-9z+2)*5)/(-20z)+16z/(-20z)=0



We calculate terms in parentheses: +(((-9z+2)*5)/(-20z)+16z/(-20z), so:

((-9z+2)*5)/(-20z)+16z/(-20z

We calculate fractions


(((-9z+2)*5)*(-20z)/((-20z)*(-20z)+(-320z^2)/((-20z)*(-20z)



We calculate terms in parentheses: +(((-9z+2)*5)*(-20z)/((-20z)*(-20z)+(-320z^2)/((-20z)*(-20z), so:

((-9z+2)*5)*(-20z)/((-20z)*(-20z)+(-320z^2)/((-20z)*(-20z

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