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((2/3)x)+(1/2)=12
We move all terms to the left:
((2/3)x)+(1/2)-(12)=0
Domain of the equation: 3)x)!=0determiningTheFunctionDomain ((2/3)x)-12+(1/2)=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
((+2/3)x)-12+(+1/2)=0
We get rid of parentheses
((+2/3)x)-12+1/2=0
We calculate fractions
()/3x)*2)+3x/3x)*2)-12=0
We can not solve this equation
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