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((2/5)x)+(4/5)=(-(4/5))
We move all terms to the left:
((2/5)x)+(4/5)-((-(4/5)))=0
Domain of the equation: 5)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((+2/5)x)+(+4/5)-((-(+4/5)))=0
We get rid of parentheses
((+2/5)x)+4/5-((-(+4/5)))=0
We calculate fractions
()/5x)*5*5))))+(-((-20x))/5x)*5*5))))=0
We can not solve this equation
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