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((24x-72)-(5x-15))/((x-3)(4x-12))=-10
We move all terms to the left:
((24x-72)-(5x-15))/((x-3)(4x-12))-(-10)=0
Domain of the equation: ((x-3)(4x-12))!=0We add all the numbers together, and all the variables
x∈R
((24x-72)-(5x-15))/((x-3)(4x-12))+10=0
We multiply parentheses ..
((24x-72)-(5x-15))/((+4x^2-12x-12x+36))+10=0
We multiply all the terms by the denominator
10*((+4x^2-12x-12x+36))+((24x-72)-(5x-15))=0
We calculate terms in parentheses: +((24x-72)-(5x-15)), so:We get rid of parentheses
(24x-72)-(5x-15)
We get rid of parentheses
24x-5x-72+15
We add all the numbers together, and all the variables
19x-57
Back to the equation:
+(19x-57)
10*((+4x^2-12x-12x+36))+19x-57=0
We move all terms containing x to the left, all other terms to the right
10*((+4x^2-12x-12x+36))+19x=57
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