((24x-72)-(5x-15))/((x-3)(4x-12))=-10

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Solution for ((24x-72)-(5x-15))/((x-3)(4x-12))=-10 equation: 



((24x-72)-(5x-15))/((x-3)(4x-12))=-10

We move all terms to the left:

((24x-72)-(5x-15))/((x-3)(4x-12))-(-10)=0



Domain of the equation: ((x-3)(4x-12))!=0

x∈R



We add all the numbers together, and all the variables

((24x-72)-(5x-15))/((x-3)(4x-12))+10=0

We multiply parentheses ..

((24x-72)-(5x-15))/((+4x^2-12x-12x+36))+10=0

We multiply all the terms by the denominator


10*((+4x^2-12x-12x+36))+((24x-72)-(5x-15))=0



We calculate terms in parentheses: +((24x-72)-(5x-15)), so:

(24x-72)-(5x-15)

We get rid of parentheses

24x-5x-72+15

We add all the numbers together, and all the variables

19x-57

Back to the equation:

+(19x-57)



We get rid of parentheses

10*((+4x^2-12x-12x+36))+19x-57=0

We move all terms containing x to the left, all other terms to the right

10*((+4x^2-12x-12x+36))+19x=57

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