((2a+3)/4)+((a-1)/3))=2

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Solution for ((2a+3)/4)+((a-1)/3))=2 equation: 



((2a+3)/4)+((a-1)/3))=2

We move all terms to the left:

((2a+3)/4)+((a-1)/3))-(2)=0

We calculate fractions


(((2a+3)*3))-2)/()+(4a-4)/()=0



We calculate terms in parentheses: +(((2a+3)*3)), so:

((2a+3)*3)



We calculate terms in parentheses: +((2a+3)*3), so:

(2a+3)*3

We multiply parentheses

6a+9

Back to the equation:

+(6a+9)



We get rid of parentheses

6a+9

Back to the equation:

+(6a+9)



We get rid of parentheses

6a-2)/()+(4a+9-4)/()=0

We calculate fractions


6a+()/((4a*()))+4a/((4a*()))+9+(-4)*()=0



We calculate terms in parentheses: +()/((4a*())), so:

)/((4a*())

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()



We add all the numbers together, and all the variables

6a+4a/((4a*()))=0

We multiply all the terms by the denominator


6a*((4a*()))+4a=0

We add all the numbers together, and all the variables

4a+6a*((4a*()))=0

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