((2a+4)/2)+((a+3)/5)=1/10

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Solution for ((2a+4)/2)+((a+3)/5)=1/10 equation: 


a in (-oo:+oo)

(2*a+4)/2+(a+3)/5 = 1/10 // - 1/10

(2*a+4)/2+(a+3)/5-(1/10) = 0

(2*a+4)/2+(a+3)/5-1/10 = 0

(5*10*(2*a+4))/(2*5*10)+(2*10*(a+3))/(2*5*10)+(-1*2*5)/(2*5*10) = 0

5*10*(2*a+4)+2*10*(a+3)-1*2*5 = 0

120*a-10+260 = 0

120*a+250 = 0

(120*a+250)/(2*5*10) = 0

(120*a+250)/(2*5*10) = 0 // * 2*5*10

120*a+250 = 0

120*a+250 = 0 // - 250

120*a = -250 // : 120

a = -250/120

a = -25/12

a = -25/12

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