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((2b)/3)+(11/4)=3-((11b)/6)
We move all terms to the left:
((2b)/3)+(11/4)-(3-((11b)/6))=0
We add all the numbers together, and all the variables
(+2b/3)-(3-(+11b/6))+(+11/4)=0
We get rid of parentheses
2b/3-(3-(+11b/6))+11/4=0
We calculate fractions
48b^2/()+(-(3-(+11b*3*4)/()+()/()=0
We calculate terms in parentheses: +(-(3-(+11b*3*4)/()+()/(), so:
-(3-(+11b*3*4)/()+()/(
We can not solve this equation
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