((2k)/5)/((6k)/10)

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Solution for ((2k)/5)/((6k)/10) equation: 


D( k )

(6*k)/10 = 0

(6*k)/10 = 0

(6*k)/10 = 0

3/5*k = 0 // : 3/5

k = 0

k in (-oo:0) U (0:+oo)

((2*k)/5)/((6*k)/10) = 0

2/3 = 0

k belongs to the empty set

k belongs to the empty set

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