((2k-8)2)+(k+2)2=4k

Solution for ((2k-8)2)+(k+2)2=4k equation:

((2k-8)2)+(k+2)2=4k

We move all terms to the left:

((2k-8)2)+(k+2)2-(4k)=0

We add all the numbers together, and all the variables

-4k+((2k-8)2)+(k+2)2=0

We multiply parentheses

-4k+((2k-8)2)+2k+4=0


We calculate terms in parentheses: +((2k-8)2), so:

(2k-8)2

We multiply parentheses

4k-16

Back to the equation:

+(4k-16)


We add all the numbers together, and all the variables

-2k+(4k-16)+4=0

We get rid of parentheses

-2k+4k-16+4=0

We add all the numbers together, and all the variables

2k-12=0

We move all terms containing k to the left, all other terms to the right

2k=12

k=12/2

k=6