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((2r)/3)-7=r+5
We move all terms to the left:
((2r)/3)-7-(r+5)=0
We add all the numbers together, and all the variables
(+2r/3)-(r+5)-7=0
We get rid of parentheses
2r/3-r-5-7=0
We multiply all the terms by the denominator
2r-r*3-5*3-7*3=0
We add all the numbers together, and all the variables
2r-r*3-36=0
Wy multiply elements
2r-3r-36=0
We add all the numbers together, and all the variables
-1r-36=0
We move all terms containing r to the left, all other terms to the right
-r=36
r=36/-1
r=-36
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