((2w-1)/2)+w+2=2w

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Solution for ((2w-1)/2)+w+2=2w equation: 


w in (-oo:+oo)

(2*w-1)/2+w+2 = 2*w // - 2*w

(2*w-1)/2+w-(2*w)+2 = 0

(2*w-1)/2+w-2*w+2 = 0

(2*w-1)/2+(2*w)/2+(-2*2*w)/2+(2^2)/2 = 0

2*w+2*w-2*2*w-1+4 = 0

4*w-4*w-1+4 = 0

4-1 = 0

3 = 0

3/2 = 0

3/2 = 0 // * 2

3 = 0

w belongs to the empty set

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