((2x)/5)+((x-4)/6)=((4x+1)/4)-2

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Solution for ((2x)/5)+((x-4)/6)=((4x+1)/4)-2 equation: 


x in (-oo:+oo)

(x-4)/6+(2*x)/5 = (4*x+1)/4-2 // - (4*x+1)/4-2

(x-4)/6-((4*x+1)/4)+(2*x)/5+2 = 0

(x-4)/6+(-1*(4*x+1))/4+(2*x)/5+2 = 0

(4*5*(x-4))/(4*5*6)+(-1*5*6*(4*x+1))/(4*5*6)+(2*4*6*x)/(4*5*6)+(2*4*5*6)/(4*5*6) = 0

4*5*(x-4)-1*5*6*(4*x+1)+2*4*6*x+2*4*5*6 = 0

48*x-100*x-110+240 = 0

240-52*x-110 = 0

130-52*x = 0

(130-52*x)/(4*5*6) = 0

(130-52*x)/(4*5*6) = 0 // * 4*5*6

130-52*x = 0

130-52*x = 0 // - 130

-52*x = -130 // : -52

x = -130/(-52)

x = 5/2

x = 5/2

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