((2x)/5)-((4x+3)/2)=1

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Solution for ((2x)/5)-((4x+3)/2)=1 equation: 


x in (-oo:+oo)

(2*x)/5-((4*x+3)/2) = 1 // - 1

(2*x)/5-((4*x+3)/2)-1 = 0

(-1*(4*x+3))/2+(2*x)/5-1 = 0

(-1*5*(4*x+3))/(2*5)+(2*2*x)/(2*5)+(-1*2*5)/(2*5) = 0

2*2*x-1*5*(4*x+3)-1*2*5 = 0

-16*x-15-10 = 0

-16*x-25 = 0

(-16*x-25)/(2*5) = 0

(-16*x-25)/(2*5) = 0 // * 2*5

-16*x-25 = 0

-16*x-25 = 0 // + 25

-16*x = 25 // : -16

x = 25/(-16)

x = -25/16

x = -25/16

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