((2x+1)/2)-((3x+1)/5)=2

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Solution for ((2x+1)/2)-((3x+1)/5)=2 equation:



((2x+1)/2)-((3x+1)/5)=2
We move all terms to the left:
((2x+1)/2)-((3x+1)/5)-(2)=0
We calculate fractions
(10x+5)/()+(-6x-2)/()-2=0
We multiply all the terms by the denominator
(10x+5)+(-6x-2)-2*()=0
We add all the numbers together, and all the variables
(10x+5)+(-6x-2)=0
We get rid of parentheses
10x-6x+5-2=0
We add all the numbers together, and all the variables
4x+3=0
We move all terms containing x to the left, all other terms to the right
4x=-3
x=-3/4
x=-3/4

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