((2x+1)/3)+16=3x

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Solution for ((2x+1)/3)+16=3x equation: 


x in (-oo:+oo)

(2*x+1)/3+16 = 3*x // - 3*x

(2*x+1)/3-(3*x)+16 = 0

(2*x+1)/3-3*x+16 = 0

(2*x+1)/3+(-3*3*x)/3+(3*16)/3 = 0

2*x-3*3*x+3*16+1 = 0

1-7*x+48 = 0

49-7*x = 0

(49-7*x)/3 = 0

(49-7*x)/3 = 0 // * 3

49-7*x = 0

49-7*x = 0 // - 49

-7*x = -49 // : -7

x = -49/(-7)

x = 7

x = 7

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