((2x+1)/4)+6=10

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Solution for ((2x+1)/4)+6=10 equation: 



((2x+1)/4)+6=10

We move all terms to the left:

((2x+1)/4)+6-(10)=0

We add all the numbers together, and all the variables

((2x+1)/4)-4=0

We multiply all the terms by the denominator


((2x+1)-4*4)=0



We calculate terms in parentheses: +((2x+1)-4*4), so:

(2x+1)-4*4

We add all the numbers together, and all the variables

(2x+1)-16

We get rid of parentheses

2x+1-16

We add all the numbers together, and all the variables

2x-15

Back to the equation:

+(2x-15)



We get rid of parentheses

2x-15=0

We move all terms containing x to the left, all other terms to the right

2x=15

x=15/2

x=7+1/2

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