((2x+1)/6)-((-5x-3)/2)=(7x-4)/3

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Solution for ((2x+1)/6)-((-5x-3)/2)=(7x-4)/3 equation: 



((2x+1)/6)-((-5x-3)/2)=(7x-4)/3

We move all terms to the left:

((2x+1)/6)-((-5x-3)/2)-((7x-4)/3)=0

We calculate fractions


6x/()+15x/()+(-14x)/()=0

We multiply all the terms by the denominator


6x+15x+(-14x)=0

We add all the numbers together, and all the variables

21x+(-14x)=0

We get rid of parentheses

21x-14x=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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