((2x+10)/2)-x=5

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Solution for ((2x+10)/2)-x=5 equation: 



((2x+10)/2)-x=5

We move all terms to the left:

((2x+10)/2)-x-(5)=0

We add all the numbers together, and all the variables

-1x+((2x+10)/2)-5=0

We multiply all the terms by the denominator


-1x*2)+((2x+10)-5*2)=0

We add all the numbers together, and all the variables

-1x*2)+((2x+10)=0

Wy multiply elements

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$

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