((2x+19)-3)/8=20/4-1x

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Solution for ((2x+19)-3)/8=20/4-1x equation: 



((2x+19)-3)/8=20/4-1x

We move all terms to the left:

((2x+19)-3)/8-(20/4-1x)=0



Domain of the equation: 4-1x)!=0

We move all terms containing x to the left, all other terms to the right

-1x)!=-4

x!=-4/1

x!=-4

x∈R



We add all the numbers together, and all the variables

((2x+19)-3)/8-(-1x+5)=0

We get rid of parentheses

((2x+19)-3)/8+1x-5=0

We multiply all the terms by the denominator


((2x+19)-3)+1x*8-5*8=0



We calculate terms in parentheses: +((2x+19)-3), so:

(2x+19)-3

We get rid of parentheses

2x+19-3

We add all the numbers together, and all the variables

2x+16

Back to the equation:

+(2x+16)



We add all the numbers together, and all the variables

(2x+16)+1x*8-40=0

Wy multiply elements

(2x+16)+8x-40=0

We get rid of parentheses

2x+8x+16-40=0

We add all the numbers together, and all the variables

10x-24=0

We move all terms containing x to the left, all other terms to the right

10x=24

x=24/10

x=2+2/5

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