((2x+3)-64x)((2x+3)+64x)=0

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Solution for ((2x+3)-64x)((2x+3)+64x)=0 equation: 



((2x+3)-64x)((2x+3)+64x)=0



We calculate terms in parentheses: +((2x+3)-64x)((2x+3)+64x), so:

(2x+3)-64x)((2x+3)+64x

We add all the numbers together, and all the variables

64x+(2x+3)-64x)((2x+3)

We get rid of parentheses

64x+2x-64x)((2x+3)+3

We add all the numbers together, and all the variables

66x-64x)((2x+3)+3

Back to the equation:

+(66x-64x)((2x+3)+3)



We add all the numbers together, and all the variables

(+2x)((2x+3)+3)=0



We calculate terms in parentheses: +(+2x)((2x+3)+3), so:

+2x)((2x+3)+3

determiningTheFunctionDomain
2x)((2x+3)+3

Back to the equation:

+(2x)((2x+3)+3)

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