((2x+3)/12)-((x-6)/8)-1=0

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Solution for ((2x+3)/12)-((x-6)/8)-1=0 equation: 



((2x+3)/12)-((x-6)/8)-1=0

We calculate fractions


(16x+24)/()+(-12x+72)/()-1=0

We multiply all the terms by the denominator


(16x+24)+(-12x+72)-1*()=0

We add all the numbers together, and all the variables

(16x+24)+(-12x+72)=0

We get rid of parentheses

16x-12x+24+72=0

We add all the numbers together, and all the variables

4x+96=0

We move all terms containing x to the left, all other terms to the right

4x=-96

x=-96/4

x=-24

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