((2x+4)*2)+(((-1)x+3)*(-1))=0

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Solution for ((2x+4)*2)+(((-1)x+3)*(-1))=0 equation: 



((2x+4)*2)+(((-1)x+3)(-1))=0



We calculate terms in parentheses: +((2x+4)*2), so:

(2x+4)*2

We multiply parentheses

4x+8

Back to the equation:

+(4x+8)





We calculate terms in parentheses: +(((-1)x+3)(-1)), so:

((-1)x+3)(-1)



We calculate terms in parentheses: +((-1)x+3)(-1), so:

(-1)x+3)(-1

determiningTheFunctionDomain
(-1)x-1+3)(

We add all the numbers together, and all the variables

(-1)x

We multiply parentheses

-x

Back to the equation:

+(-x)



We add all the numbers together, and all the variables

(-1x)

We get rid of parentheses

-x

Back to the equation:

+(-x)



We add all the numbers together, and all the variables

(4x+8)+(-1x)=0

We get rid of parentheses

4x-1x+8=0

We add all the numbers together, and all the variables

3x+8=0

We move all terms containing x to the left, all other terms to the right

3x=-8

x=-8/3

x=-2+2/3

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